Showing posts with label fluid. Show all posts
Showing posts with label fluid. Show all posts
Wednesday, May 17, 2017

Continuity Meaning

Continuity Meaning - Low Rate and the Equation of Continuity

The stream rate of a fluid is how much fluid goes through a range in a given time.

LEARNING OBJECTIVE 

Decide the stream rate in view of speed and zone or passed time and legitimize the utilization of coherence in communicating properties of a liquid and its movement

KEY POINTS 


  • Stream rate can be communicated in either term of cross-sectional zone and speed, or volume and time.
  • Since fluids are incompressible, the rate of a stream into a zone must equivalent the rate of stream out of a region. This is known as the condition of congruity.
  • The condition of coherence can demonstrate how much the speed of fluid increments on the off chance that it is compelled to course through a littler region. For instance, if the zone of a pipe is divided, the speed of the liquid will twofold.
  • Despite the fact that gasses regularly act as liquids, they are not incompressible the way fluids are thus the congruity condition does not have any significant bearing.

TERMS 

  • coherence 
The absence of intrusion or disengagement; the nature of being ceaseless in space or time.
  • incompressible 
Not able to be compacted or dense.

The stream rate of a liquid is the volume of liquid which goes through a surface in a given unit of time . It is generally spoken to by the image Q.

Stream Rate

Volumetric stream rate is characterized as

[Math Processing Error]Q=v∗a,

where Q is the stream rate, v is the speed of the liquid, and an is the territory of the cross area of the space the liquid is traveling through. Volumetric stream rate can likewise be found with

[Math Processing Error]Q=Vt

where Q is the stream rate, V is the Volume of liquid, and t is slipped by time.

Coherence

The condition of coherence works under the suspicion that the stream in will level with the stream out. This can be helpful to settle for some properties of the liquid and its movement:

Q1 = Q2 

This can be communicated from various perspectives, for instance: A1∗v1=A2∗v2. The condition of progression applies to any incompressible liquid. Since the liquid can't be packed, the measure of liquid which streams into a surface must equivalent the sum streaming out of the surface.


Applying the Continuity Equation 

You can watch the progression condition's impact in a garden hose. The water moves through the hose and when it comes to the smaller spout, the speed of the water increments. Speed increments when cross-sectional range reductions, and speed diminishes when cross-sectional region increments.

This is a result of the progression condition. In the event that the stream Q is held consistent, when the range A declines, the speed v must increment relatively. For instance, if the spout of the hose is a large portion of the territory of the hose, the speed should twofold to keep up the nonstop stream.
Thursday, February 9, 2017

Bernoulli Distribution


Bernoulli Distribution. In our everyday life, Bernoulli's principle can be used to explain the work of carburetors, venturi meters, Pitot tubes, perfume sprayer bottles and insecticide spray guns. The Bernoulli's principle is also used to calculate the leakage of the water tank.

The Application of Bernoulli's Principle


a.  Flow from a Tank Hole

A drum that is filled with water to a height h1. There is a hole in the tank which is located at a height h2. measured from the bottom of the tank. What is the speed of water flowing from that hole? The speed of the liquid in the tank (v1) is very small compared to the speed of the fluid through the hole (v2). Thus we can assume that v1 = 0. Both the water surface and the hole are affected by the atmospheric pressure, therefore P1 = P2 = P0. Based on equation
P1 + ½ pv12 + ρgh1 = P2 + ½ ρv22 ρgh2 
we have:
 ρgh1 = ½ ρv22 - ρgh2
Example
A cylindrical container having a large cross-sectional area is filled with water to a height of 170 cm. There is a narrow hole at a height of 125 cm from the bottom of the container. If g = 10m/s2. calculate (a) the escape speed of water through the hole, and (b) the distance from the container where the water stream strikes the floor.

b. The Venturi meter

A venturi pipe or venturi meter can be used to measure the flow speed of a fluid in a pipe. There are two types of venturi meter; venturi meter without manometer and venturi meter with the manometer.

1) Venturimeter without Manometer

There is no difference in height in the flow of fluid which is going be measured so the Bernoulli's equation, in this case, will be in the form of:
P1 + ½ pv12 = P2 + ½ ρv22     or
P1 - P2 = ½ ρ (v22 - pv12 )   

c. Perfume Sprayer

When we press the sprayer button of a perfume bottle, a rubber ball is compressed and the air is forced to come out through a narrow hole above a cylinder tube which has enough length to reach the perfume. The air which is moving faster causes the air pressure at the upper part of the tube to decrease, as a result the atmospheric pressure forces the liquid to rise to the upper part of the tube. Finally, a fast moving air spray blows the perfume liquid, and the perfume is flowed out as a fine mist.

d.  Insecticide Sprayer

Basically, the principle of an insecticide sprayer is the same with a perfume sprayer works by pressing the sprayer button, meanwhile, an insecticide sprayer works by pushing the pump-rod.

e.  The airplane wing

The wing is shaped is such a way that air flows more rapidly over the top of the wing than along the bottom. As a result, the pressure on top of the wing is smaller that the pressure on the bottom, therefore the net upward force (lift) is generated.

Exercise 6.2

  1. A fluid through a pipe having a cross-sectional area of 3 cm2, with a volume flow rate of 15 cm3/s. Calculate: (a) the amount of fluid flowing in one hour, and  (b) the flow speed of the fluid.
  2. A tube having different cross-sectional areas is placed in a horizontal position. The radius of each portion 2 cm and 1 cm. If the flow speed through the wider portion is 20 m/s. find out the flow speed at the narrow portion.
  3. The volume flow rate of water flowing through a hole is 100 cm3/s. The hole is 10 m deep from the water surface in a large container. If there is an additional pressure of 3 x 104 N/m2 on the surface, calculate: (a) the flow's speed of water through the hole, and (b) the volume flow rate of water through the hole.
  4. When the air flows through a Pitot tube, the difference in height between mercury columns in manometer is 2 cm. Determine the flow speed of the air.  and ρair = 1,29 kg/m3 and ρmercury = 13,6 kg/m3)
  5. An airplane with a mass of 500 kg has a total area of wings A = 50 m2. The air flows through the upper part of the wing a speed of 40 m/s ( ρ = 1.29 kg/m3). Find out the flow speed of air below the wing. ( g = 10m/s2)

Multiple Choice

1)  A pipe of a barometer is replaced with another pipe having twice the cross-sectional area the previous pipe. If the atmospheric pressure is 1 atm, the height of the mercury column is.....
a.  19 cm
b.  38 cm
c.  76 cm
d.  114 cm
e.  152 cm

2)  The water level at a dam is 5 m. If the lenght of the dam wall is 40 m, the force required by the wall to hold the water is ..........
a.  1.00 x 104 N
b.  2.50 x 105 N
c.  5.00 x 106 N
d.  2.50 x 107 N
e.  3.00 x 108 N

3)  The pressure of a liquid depends on ......
a.  The density of the object
b.  The density and volume of the object
c.  The density and depth of the liquid
d.  The volume and depth of the liquid
e.  The density, volume and depth of the liquid

4)  The pressure applied to an enclosed fluid is transmitted equally to every part of the fluid. That statement is....
a.  The principal law of hydrostatic
b.  Archimedes' principle
c.  Pascal's law
d.  Boyle's law
e.  Hooke's law

5)  The volume flow rate is defined as the amount of fluid which flows through a section of a tube in every unit if ......
a.  volume
b.  area
c.  length
d.  time
e.  mass

6)  Water flows through a pipe with a cross-sectional area of 10 m2. The time required of fully fill a container with a volume of 1 m3 is five minutes. The flow speed of the water is ..... m/s
a.  0.1
b.  0.33
c.  1/300
d.  3.33
e.  6.66

7)  Water flows into a container with a constant volume flow rate of 0.5 liters/s. If te volume of the container is 1 m3, it will be full in.....
a.  33.3
b.  3.33
c.  333
d.  0.33
e.  0.033

8)  The following devices work based on Bernoulli's principle, except ......
a.  airplane wing design
b.  hydraulic jack
c.  perfume sprayer
d.  venturi tube
e.  pitot tube

9)  A container is 20 m high. Two  holes are made in the container which is located 2 m from the surface and 2 m from the bottom of the container. The ratio between the distances where the water stream from hole 1 and hole 2 strike the floor is ......
a.   1 : 1
b.   2 : 1
c.   1 : 2
d.   3 : 2
e.   2 : 3

10)  There is a hole in a container. The hole is h1 deep from the surface and h2 high from the bottom of the container. The water strikes the floor at a maximum horizontal distance if the ratio between h1 : h2 is ......
a.   1 : 2
b. √2 : 1
c. 2 : 1
d. 1 : √2
e. 1 : 1 

Activity

Observing Capillarity and Mass Density Of Fluid

Tools :
kerosene lamp, kerosene, water, lighter
Procedure:
  1. Prepare a kerosene lamp
  2. Fill the lamp with kerosene. Make sure that the wick is not immersed.
  3. Add some water in a way that the wick is then immersed
  4. Light it on.
Question 
  1. Can you turn on the lamp? Can water be used as fuel for the lamp?
  2. Can the lamp be turned on if the wick is not wet yet by the kerosene?
  3. Explain your finding.

You Need To know

We are familiar with egg; we may even consume it every day. Do you know how to differentiate between a good and fresh egg and the rotten one?
It is very easy and simple. We can do it by putting the eggs in a basin of water. A good egg will sink to the bottom of the basin because it has a fresh yolk and album en. The density of a fresh egg is higher than the density of water (ρaegg = ρmwater). Meanwhile, the yolk and the albumen of a rotten egg are dehydrated, thus its density becomes smaller than the density of water (ρegg < ρwater). Therefore, if we put a rotten egg into the water, the egg will float.

Case Study

Mini Submarines (Mini-Sub)

A mini submarine is a specially designed submarine having different size and shapes. Inside its hull, there is a round-shaped cabin made of very thick metals. A crew man can look outside through a window. It is also equipped with very strong lamps, the sunlight could not reach the bottom of the sea. A mini-submarine is very useful for repairing the offshore oil drilling instruments, investigating the wrecked ships, and finding some valuable minerals that might exist in the seabed. A mini-sub is equipped with an arm which can be moved and controlled from the hull. The arm is able to hold or take some objects from the sea floor.

Discussion Material

A driver cannot work a very deep place below the surface without using additional equipment to protect his body. Why is that so? Is it related to the hydrostatic pressure?
Thursday, February 2, 2017

Hydrostatic Pressure Definition

A submarine can float above the water surface or dive below the water surface by emptying or filling its ballast tank. A ballast tank is cavities on a hull (larboard and starboard) of a submarine that can be filled with air or water. The submarine moves forward by using propellers and move downward by using hydroplane which looks like the tail of the airplane which pushes it downward. On the other hand, when the submarine is going to the surface, the water inside the ballast tank has to be pushed outward by the pressurized air. The working principle of a submarine agrees with Archimedes' principle. What does the Archimedes' principle state' You will study it in this article?

A. Hydrostatics

There are three states of mater, i.e.: solid, liquid, and gas. In solid, a matter retains a definite size and shape. In a liquid, a matter has a definite volume and takes the shape of its container. Liquid and gasses have an ability to flow. That is why both liquid and gasses are usually called fluid or the flowing substance. Our study or fluid will be divided into two parts, i.e. hydrostatics which discusses the static fluid or fluid at rest and hydrodynamics which discusses fluid in motion.

1. Density

Density (𝝆) of a material is defined as its mass (m) per unit volume (V). Mathematically, density is formulated as:

The SI unit of density is kg/m3; meanwhile, the cgs unit of density is g/cm3.

2. Pressure

a. Definition of Pressure

Pressure is defined as the force per unit of area.
If a force F works perpendicularly to a surface with area A, we can write the pressure P as:

The SI unit of pressure is Pascal (Pa), where 1 Pa = 1N/m2. The pressure will increase if the force applied to a given area increases or the area of a given force is reduced.

See Figure 6.3 with the same magnitude of force, the pressure given by a needle is bigger than that by a finger on a balloon. The pressure, given by a finger only causes the balloon to undergo a little deformation., whereas the same magnitude of force given by a needle is able to blast the ballon.

b. Atmospheric Pressure and Gauge Pressure

We are all used to work under the pressure called atmospheric pressure. This pressure is caused by the weight of the air above us. The value and unit of atmospheric pressure are:

Have you ever measured the air pressure in a car's tire? What do you find? Has the pressure inside the tire ever been lower than the outside air pressure? Let's examine this.
In some cases, we sometimes measure the pressure inside a certain object by calculating its difference with the outside air pressure (atmospheric pressure). Even the air pressure inside a flat tire will never be zero. A measurement of the pressure inside a flat tire will result in the value of the outside air.
To inflate a car's tire so that the pressure inside it reaches the value of 241 kPa, the pressure inside the tire must be higher than the outside air pressure in the amount of P = 241 kPa + Po = 302 kPa. The241 kPa pressure that will appear in a measurement is called gauge pressure (Pg) which is generally formulated by
Pg = P + Po

c. Pressure in a Static Fluid

We have discussed pressure as the result of the division between the working force and the surface area. We have also discussed the example of pressure comparison two equal forces acting on a different surface area (Figure 6.3). The example describes the pressure caused by mechanical force; how about the pressure caused by fluid?
The experiment result shows that fluid pushes in all directions. Thus, somebody who dives under water will feel the water pressure in whole parts of his body.
A point of fluid's particle also undergoes pressure from all directions. If the fluid is at rest, the forces acting on that point will be equal in magnitude. The direction of the compression force is always perpendicular to its contact surfaces.
Now, we area going to calculate the pressure in the bottom of a container filled with a density ρ and cross section of A (Figure 6.3). The pressure at the bottom of the container is caused by the compression force of the outside air and the weight of the fluid above it.

The top of the fluid which is in direct contact with the air will undergo a compression force of
Fbottom = Ftop + mg
The bottom of the container will undergo downward force in the amount of Ftop plus the weight of the fluid, i.e. w = m.g;
Pbottom = P0 + ρhg   ....... (6.4)
Pressure caused by a fluid at rest is called hydrostatic pressure. The hydrostatic pressure is proportional to the depth (h) and the density (P) of the fluid. Any point at the same level always has the same pressure, regardless of the shape of the container. Equation (6.4) does apply for any depths, not only the base of the container.
Example 6.1
A drum of 1 meter high is filled with kerosene ( ρ  = 0,8 g/cm3 to 3/4 of the drum's height. If g = 10m/s2, find the pressure at the bottom of the drum.
Answer :
= 800 kg/m3 ; h = 0,75 m
Pbottom =  ρgh = P0 + 800 kg/m3) (10m/s2) (0,75m) = 6,01 N/m2.

3.  Pascal's Principle

As a fluid, the earth's atmosphere exerts pressure to all materials which are contact with it, including all the fluids on the earth's surface. The atmospheric pressure applied to a fluid is transmitted to every part of the fluid. This was stated by a French philosopher and scientist, Blaise Pascal (1623-1622). Pascal's principle or commonly known as Pascal's law states that:
Pressure applied to an enclosed fluid is transmitted equally to every part of the fluid.
On of the applications of Pascal's law is the hydraulic lift, as shown, If a force F1 strikes a piston with a small area A1, the pressure of the fluid will increase the amount of P = F1/A1.  The increase of the pressure is then transferred to the cross-sectional area of a larges piston A2. Since the applied pressure is the same at both pistons, it applies:
F1/A1 = F2/A2

4. Archimedes' Principle

A sand miner finds it easier to lift a bucket of sand from a river when the bucket is still on the water. However, when the bucket is taken out of the water, it will become heavier. How can this happen?
If a body is immersed in a fluid, the fluid exerts an upward force on the body. The force makes the body as though it had less weight. This fact was firstly acknowledged by Archimedes, it is therefore known as Archimedes' principle, which states that:
When a body is immersed in a fluid, the fluid exerts an upward force (buoyant force) on the body whose magnitude is equal to the weight of the fluid displaced by the body.
Archimedes' principle is mathematically formulated as:
FA = ρfluid V g
where is a buoyant force, ρfluid is the density of the fluid, and Vt  is the volume of immersed body.
There are three possible cases of the body in a fluid, i.e floating, barely floating (completely submerged), and sinking. By using Newton's first law and Archimedes' principle, we can determine in what terms a body will be floating, barely floating, or sinking.

a)  Floating

A body is said to be floating if only some parts of the body are submerged or beneath the water surface, meanwhile the other part is above the water surface. On a floating body, the magnitude of buoyant force FA is equal
FA = mg
ρfluid g Vt = ρb Vb g
ρfluid  Vt = ρb Vb 
The volume of the body below the water surface Vt is always smaller than the total volume of the body Vb. Hence he density (ρb) of a floating body is smaller than the fluid's density ρb < ρfluid 

b) Barely Floaing (Completely Submerged)

On a barely floating body, the magnitude of buoyant force FA is equal to the body's weight w = mg, Thus, we have:
ρfluid g Vt = ρb Vb g
However, the volume of the immersed body Vt is equal to the total volume of the body Vtb . Hence for a barely floating body, we have the relation ρb = ρfluid  . Therefore on a barely floating body, the density of the body is equal to the density of fluid.

c) Sinking

When a body is sinking, it means that the buoyant force FA acts on the body is smaller than its weight mg. On a sinking body, the volume of the immersed body Vt is equal to the total volume of the body Vb. However, if the body stays at the bottom of a container, there will be a normal force N acting on it, so it goes:
 FA + N = w
N = ρb Vb g - ρfluid g Vt
Since the normal force is always positive, we have ρb < ρfluid . Thus, a body sinks in a fluid when its density is greater than the density of the fluid.

Archimedes' principle is widely used in either technology or science. Some examples of devices that work based on Archimedes' principle are hydrometers, ships, dockyards, submarines, and hot air ballons.

5) Viscosity

When sliding across a rough floor, a block experiences a frictional force opposing then motion. Similarly, a fluid flowing past a stationary surface experiences a force opposing the flow. This tendency to resist flow is referred to the viscosity of a fluid. Fluid like air have low viscosity, thicker fluid like water are more viscous, and fluids like honey and molasses are characterized by their high viscosity.

A fluid's viscosity is related to the frictional force between fluid's layers when a layer slides over him other. On liquid, the viscosity is caused mainly by the cohesive force between its molecules; meanwhile, on gas, the viscosity is caused mainly by collisions between its molecules.
The ideal fluid we often use in the discussion has zero viscosity. This is because we neglect the inter-molecule interaction of the ideal fluid. The flow of ideal fluid is laminar (streamline), every point in the fluid has an equal speed.
the true fluid with the certain value of viscosity will generate a flow pattern as. Because adjacent portions of the flow pasts one another with different speed, a force mus be exerted on the fluid to maintain the flow.
The force causing a viscous fluid to flow is provided difference by the pressure, (P1 - P2) across a given length of tube (L). Experiments show that the required pressure difference is proportional to the length of the tube (L) and the average speed of the fluid (v), and inversely proportional to the cross-sectional area of the tube (A).
We can observe viscosity by dropping a marble into a glass of cooking oil. The marble is slowed down by the fluid due  the frictional force. The magnitude of the frictional force on the marble moving at its constant velocity v in the fluid can be calculated by using the following equation:
f = 5πηrv
where is fluid's viscosity and r is the marble's radius.
When the marble is dropped into the oil, at a certain time it will move in a constant velocity. The velocity is known as terminal velocity. There are three kinds of force acting on the marble during its movement on the cooking oil,i.e. weight (w) buoyant force (FA), and frictional force of fluid (f).